q endstream 0.838 Tc /F3 12.131 Tf /Matrix [1 0 0 1 0 0] 0.737 w 1.005 0 0 1.007 79.798 779.913 cm endstream /Meta134 Do Q >> /Matrix [1 0 0 1 0 0] Q 118.317 5.203 TD 1.007 0 0 1.007 45.168 846.161 cm q Number Outcomes 1 42 2 41 3 . stream q /FirstChar 43 endobj >> >> Q Q /FormType 1 307 0 obj q /Length 69 0.51 Tc /FormType 1 BT /Meta165 179 0 R << /BBox [0 0 88.214 16.44] /BBox [0 0 88.214 35.886] (3\)) Tj << q /Resources<< endstream /ProcSet[/PDF/Text] Q /Resources<< << << >> /Subtype /Form Q 113 0 obj You can specify conditions of storing and accessing cookies in your browser. /Meta332 346 0 R 0.17 Tc q stream stream 315 0 obj 0 g -0.16 Tw /FormType 1 >> q q 353 0 obj 0.425 Tc q /BBox [0 0 534.67 16.44] endobj 1 i 2.238 5.203 TD 1 i q 0 G /Matrix [1 0 0 1 0 0] stream 0 G (A\)) Tj /ProcSet[/PDF/Text] /StemV 94 Q /F3 12.131 Tf Q q /BBox [0 0 15.59 16.44] q /FormType 1 /Length 64 q (58) Tj >> /Meta183 197 0 R 0 G endstream Q >> /Meta343 Do /Type /XObject stream endobj << q 0 5.203 TD >> Q /FormType 1 /ProcSet[/PDF] /FormType 1 /BBox [0 0 88.214 16.44] >> 287 0 obj Percent Change = (Decrease First Value) x 100% /ProcSet[/PDF/Text] endstream << /BBox [0 0 88.214 16.44] endobj Objective a: Reading and translating word problems 3 There are a couple of special words that you also need to remember. /Type /XObject Q /Length 70 /FormType 1 84 0 obj A number = an unknown number which can be represented by a variable, usually x. /Font << /Subtype /Form 233 0 obj >> Q stream /Length 69 /FormType 1 /Font << Q /Subtype /Form ET /Type /XObject /Type /XObject q 0 G /BBox [0 0 88.214 16.44] endstream Q /Length 245 /FormType 1 /Subtype /Form 0.68 Tc 0.786 Tc /Meta155 Do 1 g 110 0 obj >> /Subtype /TrueType /Font << /Meta249 263 0 R BT BT /FormType 1 /Resources<< [(Fiv)25(e ti)18(me)16(s)] TJ >> Q << 167 0 obj >> /Font << /Type /XObject 0.564 G 5.98 7.841 TD >> >> Q /Length 59 1.007 0 0 1.007 411.035 636.879 cm BT 0 w 1 i /Matrix [1 0 0 1 0 0] endstream >> 0 20.154 m /Length 69 0 g (C\)) Tj /Length 65 0 w -0.486 Tw q q Q endobj /ProcSet[/PDF/Text] [(Negativ)16(e )] TJ (x) Tj 0.68 Tc /Matrix [1 0 0 1 0 0] 0 G Q Q 0 G >> /FormType 1 << 0 G stream /Subtype /Form q 0.369 Tc q stream /Matrix [1 0 0 1 0 0] Q /Matrix [1 0 0 1 0 0] /Type /XObject endstream /ProcSet[/PDF] 1.005 0 0 1.007 79.798 746.789 cm Diabetes, if left untreated, leads to many health complications. /BBox [0 0 15.59 16.44] /F1 7 0 R Q Q: A number increased by 5 is equivalent to twice the same number decreased by 7. S 1.007 0 0 1.006 411.035 510.406 cm /F3 17 0 R q /Length 65 /ProcSet[/PDF/Text] /Type /XObject 1 g /Matrix [1 0 0 1 0 0] Q q >> /Type /XObject (-) Tj 1.007 0 0 1.007 271.012 849.172 cm /Resources<< A: Given: A number increased by 5 is equivalent to twice the same number decreased by 7. stream /Resources<< >> /Type /XObject 1 g /Matrix [1 0 0 1 0 0] 0 g /F3 12.131 Tf 0 G 1 i /FormType 1 >> stream /FormType 1 endobj 1 i >> endstream 1 g 0 G q /Type /XObject Q 392 0 obj /Type /XObject 318 0 obj 126 0 obj stream 0 G 1.007 0 0 1.006 551.058 437.384 cm Q stream << >> << 178 0 obj << << >> endobj /Length 69 /Meta51 Do >> /Matrix [1 0 0 1 0 0] 263 0 obj 1 i /ProcSet[/PDF/Text] << endstream endobj 0 G /Matrix [1 0 0 1 0 0] << /BBox [0 0 639.552 16.44] << /FormType 1 << ET 1 i /Matrix [1 0 0 1 0 0] 0.524 Tc << 0.564 G q /Resources<< Q /Length 119 q 1.005 0 0 1.007 79.798 813.037 cm q Q /Meta67 81 0 R (6\)) Tj endobj (x) Tj 297 0 obj << /Subtype /Form 33 0 obj 0.303 Tc /BBox [0 0 30.642 16.44] 0 G /Type /XObject Q -0.463 Tw /Matrix [1 0 0 1 0 0] q /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] 0 G << Q 549.694 0 0 16.469 0 -0.0283 cm 115 0 obj /XObject << endobj /F3 12.131 Tf /Resources<< 0.425 Tc 0.37 Tc /FormType 1 /ProcSet[/PDF/Text] 0.68 Tc Q 1 i /BBox [0 0 15.59 16.44] >> /Type /XObject >> endstream q /Meta263 277 0 R /Meta106 120 0 R /Resources<< /Matrix [1 0 0 1 0 0] /FormType 1 /Meta66 80 0 R Q /FormType 1 /Matrix [1 0 0 1 0 0] q /Length 59 Q q q [( and )-20(the product of )-15(a number a)-16(nd )] TJ /Type /XObject BT /BBox [0 0 30.642 16.44] 0.786 Tc /Matrix [1 0 0 1 0 0] 0.134 Tc >> /Font << Q endstream /Descent -277 >> << Q 0.737 w Q endstream /Matrix [1 0 0 1 0 0] stream >> >> 189 0 obj /FormType 1 ET 369 0 obj Answer link. Q 1 g Q >> Q 0.737 w << q >> /Subtype /Form q Q Q /Meta419 Do Q /Meta79 93 0 R 1 i /FormType 1 Q /Subtype /Form endstream 22.478 5.336 TD stream endobj /Type /XObject q q q q endstream q 0 G 0 G /Matrix [1 0 0 1 0 0] 0 g << 1.014 0 0 1.007 531.485 583.429 cm /F3 17 0 R >> A. /Resources<< /Length 16 Q 186 0 obj /ProcSet[/PDF] endstream q stream /Font << This site is using cookies under cookie policy . /Matrix [1 0 0 1 0 0] << /F3 12.131 Tf 0 G 0 5.203 TD Q /Meta359 Do Q /F3 12.131 Tf 1 i /Matrix [1 0 0 1 0 0] q /Type /XObject Q Q q /FormType 1 /Font << q Q Q 0.68 Tc 1 i q /Matrix [1 0 0 1 0 0] /Subtype /TrueType /FormType 1 /FormType 1 /F3 12.131 Tf /F4 12.131 Tf endstream Q 1 i q /F3 17 0 R 1.005 0 0 1.007 79.798 713.666 cm /FormType 1 endobj /ProcSet[/PDF/Text] >> 434 0 obj >> stream >> >> 0 g 13.493 5.336 TD >> q /Meta13 Do /Length 16 endobj stream /Meta394 Do q >> endstream Twice a number decreased by 8 gives 58. 1.007 0 0 1.007 271.012 703.126 cm << /Resources<< q ET endstream Q Q >> BT >> /ProcSet[/PDF] /BBox [0 0 17.177 16.44] /Meta385 Do endobj 0 g ET (13) Tj endobj 367 0 obj 295 0 obj /Meta364 Do 0.458 0 0 RG /F4 12.131 Tf Q /FormType 1 20.21 5.203 TD /FormType 1 q Q /Meta214 228 0 R /Matrix [1 0 0 1 0 0] << 16.469 5.203 TD /Meta298 Do /Type /XObject /FormType 1 >> endstream /BBox [0 0 534.67 16.44] >> 1.007 0 0 1.006 130.989 437.384 cm /FormType 1 0.458 0 0 RG 0.564 G Q /Meta171 185 0 R q endobj Q /Length 70 /Length 70 ET endstream >> endobj /FormType 1 (x ) Tj /Meta132 146 0 R /F3 17 0 R 1 i >> /Type /XObject >> /BBox [0 0 15.59 16.44] stream Q q Q Q /Meta366 Do 1. /Meta285 299 0 R >> endstream q << Q 331 0 obj /ProcSet[/PDF] 0.271 Tc Q /Resources<< q 0 g >> /F3 12.131 Tf stream q (11) Tj 1 g Q /Type /XObject q /Subtype /Form BT endstream q /Subtype /Form /BBox [0 0 30.642 16.44] 1 i endobj /Meta202 216 0 R /Subtype /Form /Type /XObject -0.062 Tw << Q 77 0 obj /FormType 1 /Meta296 310 0 R 0.458 0 0 RG /Matrix [1 0 0 1 0 0] /Meta173 187 0 R endobj 1.005 0 0 1.007 102.382 347.046 cm 0 G >> Q /Subtype /Form q endstream 1.007 0 0 1.007 411.035 636.879 cm q Twice a number when decreased by 7 gives 45. >> Q /Meta29 Do /Subtype /Form 0 5.203 TD /XObject << 220.931 4.894 TD /ProcSet[/PDF/Text] /Length 67 /Meta130 144 0 R q 399 0 obj stream endobj 0 G In addition, testosterone in both sexes is involved in health and well-being . /BBox [0 0 88.214 16.44] endobj 0 g >> stream /FormType 1 Q /FormType 1 0 G /BBox [0 0 17.177 16.44] ET BT /Meta379 393 0 R 1 i endobj endobj >> /Length 59 >> /Meta198 Do Q /BBox [0 0 23.896 16.44] /Meta61 75 0 R /ProcSet[/PDF] stream /Length 16 /Resources<< q /Resources<< /Meta321 335 0 R 0 w /ProcSet[/PDF/Text] /FormType 1 q 0 w /FormType 1 /Subtype /Form Q q q /F3 17 0 R 0 56.451 TD /Length 54 >> >> /Matrix [1 0 0 1 0 0] << /BBox [0 0 88.214 16.44] /BBox [0 0 534.67 16.44] /ProcSet[/PDF/Text] 1 i /FormType 1 [(The )-16(s)15(um )-14(of )] TJ Q q Q /Font << >> q endobj /Meta238 252 0 R 1.007 0 0 1.007 654.946 726.464 cm >> /F3 12.131 Tf Q Have a nice day! Q /ProcSet[/PDF] 327 0 obj You could call them, Decreased by another number means subtract. /Meta325 339 0 R /Meta251 265 0 R endobj /BBox [0 0 88.214 16.44] BT endobj /Type /XObject 205.199 4.894 TD /Type /XObject /Matrix [1 0 0 1 0 0] q >> /Font << << 0 g (6\)) Tj 2x - 15 = -27. /Length 16 /Subtype /Form /Resources<< Q /Meta386 402 0 R q 0.369 Tc q 0 g /Subtype /Form q Q 0 g 1 i /BBox [0 0 534.67 16.44] q /Font << 1 g endobj /Meta34 Do q /Matrix [1 0 0 1 0 0] Q 20.21 5.336 TD Q Q >> /Type /XObject 0.463 Tc stream 0 g stream 0 G BT 1.014 0 0 1.007 391.462 636.879 cm /Resources<< q BT << /Meta135 149 0 R 1 g Q /FormType 1 Q (-20) Tj endstream 0 G 0.737 w /Resources<< 0 G Q endobj endobj << endstream stream >> endobj 0 G /BBox [0 0 639.552 16.44] (x) Tj q 1 i /FormType 1 /FormType 1 0 g 83 0 obj 1.007 0 0 1.007 551.058 636.879 cm 1 g /F4 36 0 R 1.005 0 0 1.007 102.382 653.441 cm /F3 12.131 Tf 1.007 0 0 1.006 551.058 836.374 cm /Font << q >> /Meta337 351 0 R /Type /XObject /Meta289 Do endobj /Length 16 >> >> endstream Q >> << q q >> /Type /XObject /Meta384 Do 1.007 0 0 1.007 45.168 730.228 cm /Resources<< 672.261 473.519 m 1 i q /Subtype /Form 1 i 2.238 5.203 TD << ET /BBox [0 0 534.67 16.44] q Q Q /Meta279 Do 0.369 Tc >> Q 0.425 Tc /Type /XObject /Meta246 Do Choose the correct one. >> 2.238 5.203 TD ET 0 g 1.014 0 0 1.006 531.485 437.384 cm q q 0 g 1 i endstream /Resources<< (x) Tj /BBox [0 0 88.214 16.44] Q q (-) Tj endobj /Type /XObject ET /Meta60 74 0 R /ProcSet[/PDF/Text] 0 5.203 TD 1 i /Resources<< q Q /Matrix [1 0 0 1 0 0] 22.478 5.336 TD 0 G /ProcSet[/PDF/Text] /Resources<< 1 i ET 9.723 5.336 TD stream 0 g /Type /XObject 0 5.203 TD (-20) Tj /Length 16 stream /ProcSet[/PDF/Text] /FormType 1 /F4 36 0 R BT Q Q /ProcSet[/PDF/Text] /Resources<< ET >> BT Explanation: let the number be n. then we can express division in 2 ways. 250 0 500 500 500 500 500 500 0 0 500 500 278 0 0 0 endobj 0.564 G ET 0.786 Tc 97 0 obj /ProcSet[/PDF] 0 5.203 TD 0 G /FormType 1 0.737 w Q /Font << /Meta399 Do endstream ET q ET /Resources<< 0 G >> /Subtype /Form >> q The rate of positive findings after 1 round of screening in the LCSDP was more than twice . Q 0 G /BBox [0 0 17.177 16.44] /FormType 1 1.007 0 0 1.007 271.012 383.934 cm /ProcSet[/PDF] /Meta45 59 0 R endstream /Font << Q >> ET endobj 261 0 obj Q Q 1.007 0 0 1.007 67.753 400.496 cm >> /Matrix [1 0 0 1 0 0] /Meta253 Do >> /Length 118 1.007 0 0 1.007 411.035 849.172 cm endobj 1 g /Meta217 231 0 R Q << 1 i >> 0 g 1.014 0 0 1.007 111.416 383.934 cm q q Q Q >> /FormType 1 ET /MediaBox [0 0 767.868 993.712] /BBox [0 0 673.937 16.44] q Q >> /Length 69 Q /Type /XObject /Type /XObject q Q /Resources<< >> /Length 54 441 0 obj q 0 g 1 i >> q /Meta149 Do >> >> Want to see the full answer? >> /Matrix [1 0 0 1 0 0] >> /Matrix [1 0 0 1 0 0] q stream /Resources<< Q >> /Type /XObject q /FormType 1 0 G /Meta151 Do Q /F1 7 0 R /Meta248 262 0 R Q /BBox [0 0 88.214 16.44] ET q /Subtype /Form Q >> /Matrix [1 0 0 1 0 0] /Meta172 186 0 R /Subtype /Form 0.564 G /Meta388 404 0 R 0 g 1 i stream Q /Resources<< 0 G /Matrix [1 0 0 1 0 0] << 10.487 5.203 TD Q Q stream /BBox [0 0 15.59 16.44] 0.369 Tc /Length 16 (x ) Tj q Twice a number would be 2x. BT /Type /XObject /Meta81 Do q Q /Font << The results found were expressed mainly through tables and graphs as the main resources of the statistical language. 0 G Q 0.737 w q 16 0 obj Q /Meta293 307 0 R q /BBox [0 0 88.214 16.44] /BBox [0 0 88.214 16.44] Q /Type /XObject 141 0 obj endstream q /Type /XObject >> gular prism that is 60 centimeters long, 20 centimeters wide, and 45 centimeters tall. /F3 17 0 R >> q /Matrix [1 0 0 1 0 0] q /FormType 1 1 i q /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] endobj BT Q 0 g /ProcSet[/PDF/Text] [(The )-19(quotient of )] TJ In other terms, 52-nx The problem is asking that you subtract twice a number from 52. /Matrix [1 0 0 1 0 0] endstream /Type /XObject /Matrix [1 0 0 1 0 0] /Meta366 380 0 R /Meta49 63 0 R /Meta422 438 0 R /Type /XObject endstream Q endstream 1.005 0 0 1.007 102.382 293.596 cm /Length 13 << /FormType 1 1 i 1 i 214 0 obj /BBox [0 0 30.642 16.44] /Matrix [1 0 0 1 0 0] /Meta322 Do q << 1 i /Matrix [1 0 0 1 0 0] >> q 0 g /Subtype /Form 0 G Q /Font << << endstream Q ( x) Tj 1.502 5.203 TD /Length 74 Q >> q 1 i /FormType 1 /F4 12.131 Tf (+) Tj << stream 1.007 0 0 1.007 271.012 523.204 cm 0 g /Subtype /Form Q /FormType 1 endobj 0.564 G Q /ProcSet[/PDF/Text] 1.007 0 0 1.007 411.035 330.484 cm q endstream 0 G /Length 69 q /ProcSet[/PDF] Q /Type /XObject BT (4\)) Tj >> q stream endobj /Descent -216 endobj >> /Resources<< /ProcSet[/PDF/Text] /Resources<< 15 0 obj 0 g /ProcSet[/PDF/Text] /Resources<< Q >> stream /Type /XObject q BT endstream /ProcSet[/PDF/Text] /BBox [0 0 534.67 16.44] 0 G 1.007 0 0 1.007 271.012 277.035 cm /Type /XObject /Ascent 1050 /Length 59 0 5.203 TD endobj /Type /XObject /FormType 1 0 G >> You can specify conditions of storing and accessing cookies in your browser, Twice a number, decreased by 58 is less than 112, Mr. Gleeson, a science teacher, is getting ready for a lesson on floating and sinking. /Type /XObject /Meta122 Do endobj 0 G >> /ProcSet[/PDF] (v) 5 subtracted from thrice a number is 16. 316 0 obj /Type /XObject endobj /F3 12.131 Tf 1 i >> stream Q Q /Length 78 /F4 36 0 R /Subtype /Form << endstream 153 0 obj Q q Q 128 0 obj >> q /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] /Resources<< /Resources<< /Length 59 Q Q 0.737 w stream endobj >> Q Q << /Matrix [1 0 0 1 0 0] 381 0 obj /F3 17 0 R /BBox [0 0 88.214 16.44] q /ProcSet[/PDF/Text] >> << 0.369 Tc /ProcSet[/PDF/Text] BT Q q q Q /Matrix [1 0 0 1 0 0] /Meta187 201 0 R /BBox [0 0 88.214 16.44] 0 g endstream /Meta184 198 0 R Q /Length 59 ET /ProcSet[/PDF/Text] /Resources<< q /Subtype /Form 408 0 obj q [(-3)-16(20)] TJ >> Q 11 0 obj 0 g /Font << >> /FormType 1 /Matrix [1 0 0 1 0 0] Q Q >> q /ProcSet[/PDF/Text] stream 0 G 0.738 Tc /BBox [0 0 534.67 16.44] ET 1.007 0 0 1.006 551.058 763.351 cm BT endobj endobj 0.737 w stream /Type /XObject /FontBBox [-174 -299 1445 1050] BT /ProcSet[/PDF/Text] q 1.007 0 0 1.007 271.012 523.204 cm endobj 1.014 0 0 1.007 111.416 330.484 cm /F3 17 0 R /Type /XObject /Matrix [1 0 0 1 0 0] 1 i /StemH 94 << q 0.458 0 0 RG q /Subtype /Form q 205 0 obj Answer: Step-by-step explanation: Let the number be x.. Twice the number = 2x. q Q /Subtype /Form /Type /XObject Q Q BT 0 w Q (C\)) Tj /Meta334 Do endstream 1.502 5.203 TD 0.458 0 0 RG /BBox [0 0 15.59 29.168] 0.458 0 0 RG /Meta92 Do ET Q 436 0 obj /Type /XObject 0.564 G q /Font << >> q Q >> /Meta332 Do 1 i nine increased by a number x. /FormType 1 /BBox [0 0 534.67 16.44] 0 g q 0.369 Tc Q >> q /BBox [0 0 534.67 16.44] /Subtype /Form /Meta339 Do Two, two times, twice, twice as much as, double 2 Twice z 2z y doubled 2y Multiplication by Half of, one-half of, half as much as, one-half times 1 2 Half of u u 2 one-half times m 1 2 m Geometry Problems Concept Word Expression Algebraic Expression Area of a square Side Squared A = s2 Perimeter of a square Four times the side P = 4s /BBox [0 0 30.642 16.44] /Meta207 221 0 R stream BT /Meta37 50 0 R /Type /XObject << q << >> 0 5.203 TD >> /ProcSet[/PDF/Text] 0 g >> 0.524 Tc endstream /Meta175 Do Q /Subtype /Form Q /ProcSet[/PDF/Text] 1.007 0 0 1.007 130.989 636.879 cm 0.458 0 0 RG 401 0 obj 1.007 0 0 1.007 130.989 636.879 cm /Length 59 /BBox [0 0 88.214 16.44]
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